Magician Monster Hunt #1 (25/26)

Magician Monster Hunt #1 (25/26)

8th Grade

30 Qs

quiz-placeholder

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Magician Monster Hunt #1 (25/26)

Magician Monster Hunt #1 (25/26)

Assessment

Quiz

Mathematics

8th Grade

Hard

CCSS
3.OA.D.8, 3.OA.D.9, 7.SP.C.7A

+10

Standards-aligned

Created by

Chad Collins

FREE Resource

30 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Seven more than twice what number equals thirty-five?

14

15

16

17

Answer explanation

If the result is 35 when you double the number and add seven, we will start by subtracting 7 from 35 to get 28. So, our number is half of 28, which is 14. To solve algebraically, we first let n represent our unknown. Then we have 2n + 7 = 35. Subtracting 7 from each side yields 2n = 28. Then we divide each side by 2 to get n = 14.

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

If x is 3 more than y, and y is 5 less than z, then what is z - x?

2

5

8

10

Answer explanation

We are told that x = y + 3 and y = z − 5, which can be rewritten as y + 5 = z. We are asked to determine the value of z − x. Substituting we get (y + 5) − (y + 3) = y + 5 − y − 3 = 5 − 3 = 2.

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

My sister and I are buying a TV for $299. I will pay $45 more than my sister. How much does my sister pay?

$127

$129

$132

$136

Answer explanation

We are told that the television costs $299 and the older sibling will pay $45 more than the younger sibling. That means that the other 299 − 45 = 254 dollars will be split equally between the two siblings. Therefore, the younger sibling will pay 254 ÷ 2 = 127 dollars.

Tags

CCSS.3.OA.D.8

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Kevin, Cindi, and Marcus have 1020 widgets. Marcus has half as many as Cindi. Kevin has 219. How many does Cindi have?

267

401

534

801

Answer explanation

See (Turning Word Problems Into Algebra Video) for steps.

Tags

CCSS.4.OA.A.3

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A fraction increases by 1 when the numerator increases by 6. If the denominator increases by 36, it decreases by 1. What is the original fraction?

3/5

4/6

5/7

6/9

Answer explanation

Let the fraction be x/y. From the conditions, (x+6)/y = x/y + 1 and x/(y+36) = x/y - 1. Solving these gives x = 3 and y = 5, so the original fraction is 3/5.

Tags

CCSS.5.NF.B.5B

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Douglas writes down his favorite number, which is a two-digit positive integer. He then turns the number into a three-digit number by writing a 7 at the end of his favorite number. This new number is 385 more than Douglass favorite number. What is Douglass favorite number?

42

63

53

65

Answer explanation

This problem can be solved several ways. First let’s solve it algebraically. We are told that Douglas’ favorite number is a positive two-digit integer; let’s call it AB where A is the tens digit and B is the units digit. That means that the value of his favorite number is 10A + B. Then a new number is created, AB7, where A now is the hundreds digit, B now is the tens digit and 7 is the units digit. The value of the new number is 100A + 10B + 7. Finally, we are told that the new number is 385 more than Douglas’ favorite number. So we have 100A + 10B + 7 = 10A + B +385. Subtracting 10A, B and 7 from both sides yields 90A + 9B = 378. Dividing both sides by 9 gives us 10A + B = 42. This is Doug’s favorite number.

Tags

CCSS.3.OA.D.8

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A pound has pit bulls, chihuahuas, and mutts. All but 23 are pit bulls, all but 17 are chihuahuas, all but 28 are mutts. How many dogs total?

31

34

35

36

Answer explanation

Let p represent the number of pit bulls, c is the number of chihuahuas and m is the number of mutts. The second sentence of the problem yields the following equations, where A is the total number of dogs: p = A − 23, c = A − 17, m = A − 28 and A = p + c + m. If we add the first three equations we get p + c + m = 3A − 68. Substituting, we get A = 3A − 68. We now solve to determine that the total number of dogs at the pound is 2A = 68 → A = 34 dogs.

Tags

CCSS.6.EE.B.7

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