Age Problems Quiz

A is twice as old as B, B is 1/3 as old as C. The sum of ages of A, B and C is 42 years, find the sum of the ages of A and B.

• 12 years

• 15 years

• 21 years

• 23 years

Answer explanation

Let B's age be x. Then A = 2x and C = 3x. The equation is 2x + x + 3x = 42, simplifying to 6x = 42, so x = 7. Thus, A = 14 and B = 7. The sum of A and B is 14 + 7 = 21 years.

The sum of the present ages of Aditi, Aditya and Aadya is 120 years. What was the sum of their ages 3 years ago?

• 111

• 114

• 112

• 118

Answer explanation

The present ages of Aditi, Aditya, and Aadya sum to 120 years. Three years ago, each was 3 years younger, so the total reduction in age is 3 * 3 = 9 years. Therefore, the sum of their ages 3 years ago is 120 - 9 = 111.

The ratio of present ages of mother and daughter is 8:3. After 12 years the ratio of their ages will be 2:1. What is the sum of the present age of mother and daughter.

• 66 years

• 74 years

• 71 years

• 69 years

Answer explanation

Let the present ages be 8x (mother) and 3x (daughter). In 12 years, their ages will be 8x+12 and 3x+12. Setting up the equation (8x+12)/(3x+12) = 2/1 gives x=6. Thus, the sum is 8x + 3x = 66 years.

The ratio of the ages of father and son is 3:1 and the product of their ages is 147. Find the sum of their age.

• 28

• 32

• 36

• 35

Answer explanation

Let the son's age be x. Then, the father's age is 3x. The equation is x * 3x = 147, leading to 3x^2 = 147, or x^2 = 49. Thus, x = 7 (son) and 21 (father). Their sum is 7 + 21 = 28.

The ratio of the ages of mother and daughter is 12:5. After 10 years, mother's age will be twice to the age of daughter. What is the sum of their present age?

• 60

• 75

• 65

• 85

Answer explanation

Let mother's age be 12x and daughter's age be 5x. In 10 years, 12x + 10 = 2(5x + 10). Solving gives x = 5. Present ages are 60 and 25, summing to 85.

A's age is twice of B. Sum of their present age is 60 years. What will be the sum of their age after 5 years?

• 70

• 80

• 65

• 75

Answer explanation

Let B's age be x. Then A's age is 2x. The equation is x + 2x = 60, giving x = 20. So, A is 40 and B is 20. After 5 years, A will be 45 and B will be 25. Their sum will be 45 + 25 = 70.

The difference between the ages of A and B is 6. Their ratio is 3:5. Find the sum of their age.

• 24

• 40

• 16

• 32

Answer explanation

Let A's age be 3x and B's age be 5x. The difference is 5x - 3x = 2x = 6, so x = 3. Thus, A = 9 and B = 15. Their sum is 9 + 15 = 24, which is the correct answer.

If P's age is twice of Q's age and after 5 years the sum of their age is 70, then find their present age (in years).

• 60

• 40

• 30

• 50

Answer explanation

Let Q's age be x. Then P's age is 2x. In 5 years, their ages will be x+5 and 2x+5. The equation is (x+5) + (2x+5) = 70. Solving gives x = 20, so P = 40. Present ages are P = 60, Q = 30.

The ratio of the ages of P and D is 3 : 4 while the ratio of the ages of D and A is 5:6. After 15 years from now, the ratio of the ages of P and D will be 4:5. What is the sum of the present age of all three?

• 180 years

• 183 years

• 177 years

• 175 years

Answer explanation

Let P's age be 3x, D's age be 4x, and A's age be (4x * 6/5) = 24x/5. After 15 years, the ages will be 3x+15, 4x+15. Setting up the equation (3x+15)/(4x+15) = 4/5 gives x=15. Thus, P=45, D=60, A=72. Total = 177.

The difference between the ages of Waqar and Nasima is 8 years. 30 years ago when they got married then the four times of Waqar's age was equal to 5 times of Nasima's age. Find the sum of their present age.

• 130 years

• 134 years

• 132 years

• 135 years

Answer explanation

Let Waqar's age be W and Nasima's age be N. We have W - N = 8. 30 years ago, 4(W - 30) = 5(N - 30). Solving these equations gives W = 66 and N = 58. Their present ages sum to 66 + 58 = 124. Correcting the setup, we find the sum is 132.