A 2.5 Solving Absolute Value Equations I

The solution set to an absolute value equation is shown. Write an absolute value equation which could be used to obtain the solution.

• |x – 1| = 5

• |x + 1| = 5

• |x – 5| = 1

• |x + 5| = 1

The solution set to an absolute value equation is shown. Write an absolute value equation which could be used to obtain the solution.

• |x + 3| = 5

• |x - 3| = 5

• |x + 5| = 3

• |x - 5| = 3

The solution set to an absolute value equation is shown. Write an absolute value equation which could be used to obtain the solution.

• |x – 1.5| = 2.5

• |x + 1.5| = 2.5

• |x – 2.5| = 1.5

• |x + 2.5| = 1.5

Solve the absolute value equation algebraically.

2|a – 17| = 10

• {12, 22}

• {10, 24}

• {15, 19}

• {8, 26}

Solve the absolute value equation algebraically.

4|2 – 9y| = 28

• {-5/9, 1}

• {-1, 5/9}

• {5/9, 1}

• {-5/9, -1}

Solve the absolute value equation algebraically.

|x – 3|/5 = 2

• {-7, 13}

• {7, -13}

• {8, -8}

• {5, -5}

Solve the absolute value equation algebraically. (3/5)|10 – 5x| + 8 = 29

• {-5, 9}

• {5, -9}

• {1, -1}

• {0, 4}

Solve the absolute value equation algebraically.

– |3x + 6| + 14 = 5

• {1, -5}

• {2, -4}

• {0, -6}

• {3, -3}

The packing material for a particular computer needs to be within 0.5 mm of the desired thickness, which is 27.5 mm. Write an absolute value equation which represents the limits of the width of the packing material.

• |x – 27.5| = 0.5

• |x + 27.5| = 0.5

• |x – 0.5| = 27.5

• |x + 0.5| = 27.5

Tags

CCSS.HSA.CED.A.3

• 3, -3

• 4, -4

• 1, -21

• 0, -2

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3