
Mastering Quadratic Equations
Authored by SKMathsClasses SK
Others
10th Grade

AI Actions
Add similar questions
Adjust reading levels
Convert to real-world scenario
Translate activity
More...
Content View
Student View
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Solve for x: x^2 - 5x + 6 = 0.
x = 2, x = 3
x = 5
x = 4
x = 1
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Graph the function: f(x) = x^2 - 4.
The vertex of the graph is at (0, 0) with no x-intercepts.
The graph of f(x) = x^2 - 4 is a parabola opening upwards with vertex at (0, -4) and x-intercepts at (-2, 0) and (2, 0).
The graph of f(x) = x^2 - 4 is a straight line with a slope of 2.
The graph opens downwards and has a vertex at (0, 4).
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Identify the vertex of the quadratic: y = 2x^2 + 8x + 3.
(-1, 2)
(0, 3)
(-3, -4)
(-2, -5)
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Factor the expression: x^2 + 7x + 10.
(x + 2)(x + 5)
(x + 1)(x + 10)
(x + 3)(x + 4)
(x - 2)(x - 5)
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Use the quadratic formula to solve: 3x^2 - 12x + 9 = 0.
x = -1, 5
x = 1, 3
x = 0, 4
x = 2, 2
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the axis of symmetry for the function: y = -x^2 + 6x - 8?
x = 4
x = 0
x = 3
x = 2
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Graph the function: f(x) = -2x^2 + 4x + 1.
The vertex of the parabola is at (0, 1) with no x-intercepts.
The graph is an upward-opening parabola with vertex at (1, 1).
The graph of the function is a downward-opening parabola with vertex at (1, 3), y-intercept at (0, 1), and x-intercepts at (2, 0) and (-0.5, 0).
The y-intercept is at (0, 4) and x-intercepts at (1, 0) and (3, 0).
Access all questions and much more by creating a free account
Create resources
Host any resource
Get auto-graded reports

Continue with Google

Continue with Email

Continue with Microsoft
or continue with
%20(1).png)
Apple
Others
Already have an account?