HYPERBOLA (EAMCET) EXERCISE

If the latus rectum of an hyperbola be 8 and eccentricity be 3/√5, then the equation of the hyperbola is

The length of the transverse axis of a hyperbola is 7 and it passes through the point (5, -2). The equation of the hyperbola is

• None of these

If (0, ± 4) and (0, ± 2) be the foci and vertices of a hyperbola, then its equation is

The equation of the hyperbola whose directrix is x + 2y = 1, focus (2, 1) and eccentricity 2 will be

• None of these

The equation of a hyperbola, whose foci are (5, 0) and (-5, 0) and the length of whose conjugate axis is 8, is

The equation of the hyperbola referred to its axes as axes of coordinate and whose distance between the foci is 16 and eccentricity is √2, is

The equation of the hyperbola referred to the axis as axes of co-ordinate and whose distance between the foci is 16 and eccentricity is √2, is

• 115x - 117y = 17

• 125x - 48y = 481

• 127x + 33y = 341

• 15x + 121y = 105