Simple Harmonic Motion

The maximum displacement from equilibrium of a particle is 1 m and its maximum acceleration is

1.57 m s^-2. The period of the particle will be

• 1.25 s

• 0.63 s

• 0.20 s

• 5.03 s

If a simple harmonic oscillator has a displacement of 0.02 m and acceleration equal to 2.00 m s^-2, the angular frequency is equal to:

• 10.0 rad s^-1

• 0.10 rad s^-1

• 100 rad s^-1

• 1.00 rad s^-1

Given equation of SHM, x=0.34 cos 3000t where x in mm and t in second. The frequency is:

• 3000 Hz

• 3000/2π Hz

• 0.74/2π Hz

• 3000/π Hz

The acceleration of a particle in SHM is:

• always zero

• always constant

• maximum at amplitude

• maximum at the equilibrium position

The variation of the acceleration, a of a particle executing SHM with displacement, x is as shown in figure:

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• 
• 

The displacement x, for a particle at time t in simple harmonic motion is given by the equation, x = 10 sin 20t where x is in meters and t is in seconds. Determine the displacement at t=10 s

• 91.3 m

• 8.73 m

• -91.3 m

• -8.73 m

When is the pendulum at 0 velocity

• At its lowest point

• At its highest point

• It moves at a constant velocity

• It is at rest

The graph shows the variation with time of the displacement of an object undergoing simple harmonic motion. At which of the following time values is kinetic energy zero?

• 0 ms

• 40 ms

• 80 ms

• 100 ms

A body executes simple harmonic motion. Which one of the graphs, A to D, best shows the relationship between the kinetic energy, E_k, of the body and its distance from the centre of oscillation?

• A

• B

• C

• D

A particle of mass 0.20 kg moves with simple harmonic motion of amplitude 2.0 × 10^–2m.

If the total energy of the particle is 4.0 × 10^–5J, what is the time period of the motion?

• 0.79 s

• 1.57 s

• 3.14 s

• 6.28 s