2019 #5 Free Response Question - AP Physics 1 - Exam Solution

In a tube open at both ends resonating at its fundamental frequency, where are the displacement antinodes located?

• At the center of the tube only.

• At both ends of the tube only.

• At both ends and the center of the tube.

• There are no displacement antinodes in an open-open tube.

For a tube open at both ends resonating at its fundamental frequency, what is the relationship between the length of the tube (L) and the wavelength (λ) of the sound wave?

• L = λ

• L = 2λ

• L = λ/2

• L = λ/4

What is the length of a tube open at both ends if a 512 Hz tuning fork causes it to resonate at its fundamental frequency, and the speed of sound in air is 340 m/s?

• 0.66 m

• 0.33 m

• 0.17 m

• 1.32 m

When an open-open tube resonates at its fundamental frequency, how does the maximum speed of air molecules vary along the length of the tube?

• Maximum at the center, zero at the ends.

• Zero at the center, maximum at the ends.

• Uniformly distributed along the tube.

• Maximum at one end, zero at the other.

What is the nature of air particle movement at an open end of a tube when a standing wave is formed?

• A displacement node, meaning no movement.

• A displacement antinode, meaning maximum movement.

• A pressure node, meaning maximum pressure variation.

• A pressure antinode, meaning no pressure variation.

For a tube open at both ends resonating at its fundamental frequency, where would you find a displacement node?

• At both ends of the tube.

• At the center of the tube.

• At L/4 and 3L/4 from one end.

• Nowhere in the tube.

When a tube is open at one end and closed at the other, what type of displacement occurs at the closed end?

• A displacement antinode.

• A displacement node.

• A pressure antinode.

• Both a displacement and pressure antinode.

For a tube open at one end and closed at the other, resonating at its fundamental frequency, what is the relationship between the tube's length (L) and the wavelength (λ) of the sound wave?

• L = λ/2

• L = λ

• L = 2λ

• L = λ/4