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Mass to Mass Stoichiometry

Authored by Xiaotian Zhang

Chemistry

10th - 11th Grade

NGSS covered

Used 28+ times

Mass to Mass Stoichiometry
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7 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

CH4 + 2O2 --> 2H2O + CO2
What is the mass of CO2 produced when 35g of O2 reacts? 

1.09 g
24.1 g
28.2 g
44.0 g

Tags

NGSS.HS-PS1-7

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Cl2 + 2KBr → Br2 + 2KCl

How many grams of potassium chloride (KCl) can be produced from 356 g of potassium bromide (KBr)?

749 g

223 g

479 g

814 g

Tags

NGSS.HS-PS1-7

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

From the reaction: B2H6 + 3O2 -->2 HBO2 + 2 H2O

What mass of O2 will be needed to burn 36.1 g of B2H6?

13.8 g O2

3.91 mol of O2

125 g O2

41.7 g O2

Tags

NGSS.HS-PS1-7

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

2Na + 2H2O → 2NaOH+ H2
How many grams of hydrogen are produced if 120 g of Na are available?

5.2 g
2.6 g
690 g
45 g

Tags

NGSS.HS-PS1-7

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the correct first step in solving any mass‑to‑mass stoichiometry problem?

Use the mole ratio to convert moles of the given substance to moles of the unknown

Convert the given mass of a substance into moles

Convert moles of the unknown substance into grams

Add the molar masses of all reactants

Tags

NGSS.HS-PS1-7

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After converting the given mass to moles, what is the next step in a mass‑to‑mass stoichiometry calculation?

Convert the moles of the given substance directly into grams of the unknown

Use the mole ratio from the balanced equation to find moles of the unknown substance

Add the molar masses of all reactants

Convert grams of the unknown into moles

Tags

NGSS.HS-PS1-7

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final step in solving a mass‑to‑mass stoichiometry problem?

Use the mole ratio to convert moles of the given substance to moles of the unknown

Convert the given mass into moles

Convert moles of the unknown substance into grams using its molar mass

Balance the chemical equation again to check your work

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