Solving Quadratic Equations with Square Roots

What is the general form of a quadratic equation?

• ax^2 + bx + c = 0

• bx^2 + ax + c = 0

• ax^2 + c = 0

• ax + b = 0

Tags

CCSS.HSA-REI.B.4B

If B equals zero in a quadratic equation, which method can be used to solve it?

• Graphing

• Completing the square

• Factoring

• Using square roots

Tags

CCSS.8.EE.A.2

What are the solutions to the equation x^2 = 25?

• x = ±5

• x = 5

• x = 0

• x = -5

Tags

CCSS.8.EE.A.2

When solving x^2 = 25, why do we consider both positive and negative roots?

• Because the square root of a number can be both positive and negative

• Because squaring a number always gives a positive result

• Because it simplifies the equation

• Because the equation is quadratic

Tags

CCSS.8.EE.A.2

In the equation 2x^2 + 3 = 75, what is the first step to isolate the squared term?

• Multiply both sides by 2

• Divide both sides by 2

• Subtract 3 from both sides

• Add 3 to both sides

Tags

CCSS.HSA-REI.B.4B

After isolating the squared term in 2x^2 + 3 = 75, what is the next step?

• Multiply both sides by 2

• Subtract 3 from both sides

• Divide both sides by 2

• Add 3 to both sides

Tags

CCSS.HSA-REI.B.4B

What is the solution to the equation 2x^2 + 3 = 75 after isolating the squared term and taking the square root?

• x = ±6

• x = 6

• x = -6

• x = 0

Tags

CCSS.HSA-REI.B.4B

In the equation y^2 - 50 = -5y^2 + 4, what is the first step to gather the squared terms?

• Add 50 to both sides

• Subtract 5y^2 from both sides

• Subtract 50 from both sides

• Add 5y^2 to both sides

Tags

CCSS.HSA-REI.B.4B

After gathering the squared terms in y^2 - 50 = -5y^2 + 4, what is the next step?

• Divide both sides by 6

• Multiply both sides by 6

• Add 50 to both sides

• Subtract 50 from both sides

Tags

CCSS.HSA-REI.B.4B

What is the final solution to the equation y^2 - 50 = -5y^2 + 4 after isolating the squared term and taking the square root?

• y = ±9

• y = ±3

• y = 3

• y = -3

Tags

CCSS.HSA-REI.B.4B