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Finding the LCM of Three Numbers with Prime Factorization

Finding the LCM of Three Numbers with Prime Factorization

Assessment

Interactive Video

Mathematics

6th - 10th Grade

Practice Problem

Hard

CCSS
4.OA.B.4, 6.EE.A.1, 3.OA.C.7

Standards-aligned

Created by

Sophia Harris

FREE Resource

Standards-aligned

CCSS.4.OA.B.4
,
CCSS.6.EE.A.1
,
CCSS.3.OA.C.7
In this video, Mr. J explains how to find the least common multiple (LCM) of three numbers using prime factorization. He demonstrates the process with the numbers 21, 28, and 32, breaking each down into their prime factors. The video covers aligning these factors vertically and calculating the LCM by multiplying the necessary factors. This method is particularly useful for larger numbers where listing multiples is inefficient.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is one advantage of using prime factorization to find the LCM over listing multiples?

It is easier to understand.

It is more efficient for larger numbers.

It requires less mathematical knowledge.

It is faster for smaller numbers.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the prime factors of 21?

2 and 14

3 and 7

2 and 7

3 and 14

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a prime factor of 28?

2

32

21

14

Tags

CCSS.4.OA.B.4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many times do you need to break down the number 32 to get its prime factors?

3 times

4 times

2 times

5 times

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When listing the prime factors of 21, 28, and 32, which number is matched vertically first?

2

3

7

None of the above

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many columns of 2s are there when matching the prime factors of 21, 28, and 32?

5

3

2

4

Tags

CCSS.4.OA.B.4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the next step after listing and matching the prime factors vertically?

Adding the numbers in each column

Dividing the numbers in each column

Multiplying the numbers in each column

Bringing down a number to represent each column

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