What is the first step in solving the problem according to the first method?

• Find the perimeter of the rectangles

• Find the area of the smaller rectangle

• Combine the areas of both rectangles

• Find the width of the larger rectangle

What is the area of the smaller rectangle if its length is 2 and its width is X?

• 2X

• X^2

• 2 + X

• 2X + 2

Tags

CCSS.7.EE.A.1

What is the area of the larger rectangle if its length is 2 and its width is 8?

• 10

• 2X

• 8

• 16

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

Why can't the terms 2X and 16 be combined?

• They are both variables

• They are already combined

• They are not like terms

• They are both constants

Tags

CCSS.6.EE.A.2B

What is the final expression obtained using the first method?

• 2X + 2

• 2X + 8

• 2X + 16

• X + 16

Tags

CCSS.7.EE.A.1

In the second method, what is the width of the large rectangle?

• 2

• X

• X + 8

• 8

Tags

CCSS.8.EE.C.7B

What property is used to solve the problem in the second method?

• Distributive Property

• Identity Property

• Commutative Property

• Associative Property

Tags

CCSS.1.OA.B.3