Dividing Quadratics by Linear Expressions with Remainders

The video tutorial explains how to simplify the expression (x^2 + 5x + 8) / (x + 2) using two methods: factoring and algebraic long division. Initially, the instructor attempts to factor the numerator but finds it challenging to find suitable factors. Instead, they rewrite the expression to make it divisible by (x + 2) and simplify it. The video then demonstrates algebraic long division, which is more straightforward in this case, resulting in a quotient of x + 3 with a remainder of 2. The tutorial emphasizes the importance of considering the domain when simplifying expressions.

What is the initial problem presented in the video?

• Solve x^2 + 5x + 8 = 0

• Simplify x^2 + 5x + 8 over x + 2

• Integrate x^2 + 5x + 8

• Find the roots of x^2 + 5x + 8

Tags

CCSS.HSA-REI.B.4B

What are the two methods suggested to simplify the given expression?

• Factoring and completing the square

• Factoring and algebraic long division

• Algebraic long division and substitution

• Substitution and completing the square

Tags

CCSS.HSA.APR.D.6

Why was the initial attempt to factor the numerator unsuccessful?

• Because the numbers did not multiply to 5

• Because the numbers did not add up to 5

• Because the numbers did not multiply to 8

• Because the numbers did not add up to 8

What was the modified expression used to make the numerator divisible by x + 2?

• x^2 + 5x + 6 + 2

• x^2 + 5x + 8 + 2

• x^2 + 5x + 8 - 2

• x^2 + 5x + 6 - 2

Tags

CCSS.HSA.APR.D.6

What is the first step in algebraic long division?

• Divide the highest degree term of the numerator by the highest degree term of the denominator

• Multiply the highest degree term of the numerator by the highest degree term of the denominator

• Subtract the highest degree term of the numerator from the highest degree term of the denominator

• Add the highest degree term of the numerator to the highest degree term of the denominator

Tags

CCSS.HSA.APR.D.6

What is the result of dividing x^2 by x in the long division process?

• 1

• x

• 2x

• x^2

Tags

CCSS.HSA.APR.D.6

What is the remainder when x^2 + 5x + 8 is divided by x + 2?

• 1

• 0

• 3

• 2

Tags

CCSS.HSA.APR.B.2

What must be done to the domain when simplifying the expression?

• Constrain it to exclude x = 2

• Constrain it to exclude x = -2

• Constrain it to exclude x = 0

• Constrain it to exclude x = 1

Why is the remainder important in the division process?

• It shows the part of the denominator that can be divided by the numerator

• It shows the part of the denominator that cannot be divided by the numerator

• It shows the part of the numerator that cannot be divided by the denominator

• It shows the part of the numerator that can be divided by the denominator

Why is algebraic long division considered more straightforward in this case?

• Because it avoids complex subtraction

• Because it avoids complex addition

• Because it avoids complex multiplication

• Because it avoids complex factoring

Tags

CCSS.HSA.APR.D.6