Exploring Adding and Subtracting Rational Expressions

What is the result of dividing 21a^5b^3 by 7ab?

• 3a^5b^2

• 3a^5b^3

• 3a^4b^2

• 3a^4b^3

Tags

CCSS.HSA.APR.D.6

When dividing by a monomial, what operation is performed on the exponents?

• Add the exponents

• Subtract the exponents

• Multiply the exponents

• Divide the exponents

Tags

CCSS.8.EE.A.1

What is the first step in dividing a polynomial by a binomial using factoring?

• Rewrite the polynomial as a fraction

• Subtract the polynomial from the binomial

• Add the polynomial to the binomial

• Multiply the polynomial by the binomial

Tags

CCSS.HSA.APR.D.6

In the expression (4h^2 - 7h - 2) / (h - 2), what is the factored form of the numerator?

• (h + 2)(4h + 1)

• (h + 2)(4h - 1)

• (h - 2)(4h - 1)

• (h - 2)(4h + 1)

Tags

CCSS.HSA.APR.D.6

What is the result of dividing (2n^3 + 3n^2 - 16n - 24) by (2n + 3)?

• n^2 + 8n

• n^2 - 8

• n^2 - 8n

• n^2 + 8

Tags

CCSS.HSA.APR.D.6

What is the first step in polynomial long division?

• Subtract the first term of the dividend from the first term of the divisor

• Divide the first term of the dividend by the first term of the divisor

• Multiply the first term of the dividend by the first term of the divisor

• Add the first term of the dividend to the first term of the divisor

Tags

CCSS.HSA.APR.D.6

What is the result of dividing (k^3 - 8k^2 - 3k + 8) by (k - 1) using long division?

• k^2 - 7k - 10 - 2/(k - 1)

• k^2 + 7k - 10 + 2/(k - 1)

• k^2 - 7k - 10 + 2/(k - 1)

• k^2 + 7k - 10 - 2/(k - 1)

Tags

CCSS.HSA.APR.D.6

How do you handle a missing power in the dividend during polynomial division?

• Ignore the missing power

• Use 0 as the coefficient for the missing power

• Subtract 1 as the coefficient for the missing power

• Add 1 as the coefficient for the missing power

Tags

CCSS.HSA.APR.D.6

What is the result of dividing (a^4 + 8a^3 - 3a - 16) by (a + 8) when a^2 is missing?

• a^3 - 3 - 8/(a + 8)

• a^3 - 3 + 8/(a + 8)

• a^3 + 3 - 8/(a + 8)

• a^3 + 3 + 8/(a + 8)

Tags

CCSS.HSA.APR.D.6

What is the final answer for dividing (3a^4 - 20a^2 - 6a + 14) by (a + 2) using long division?

• 3a^3 - 6a^2 - 8a + 10 + 6/(a + 2)

• 3a^3 - 6a^2 - 8a + 10 - 6/(a + 2)

• 3a^3 + 6a^2 - 8a + 10 - 6/(a + 2)

• 3a^3 + 6a^2 - 8a + 10 + 6/(a + 2)

Tags

CCSS.HSA.APR.D.6