Solving Two-Step Equations in Algebra

What is the first step in setting up the equation for the given problem?

• Multiply both sides by one-third.

• Remove the 1kg blocks from both sides.

• Identify the total mass on the left-hand side.

• Identify the total mass on the right-hand side.

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CCSS.HSA.CED.A.3

How many unknown masses with mass X are on the left-hand side of the scale?

• Two

• Five

• Four

• Three

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CCSS.6.EE.B.7

What is the total mass on the right-hand side of the scale?

• 16 kg

• 14 kg

• 12 kg

• 18 kg

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CCSS.3.MD.A.2

What mathematical operation is performed to remove the 1kg blocks from both sides?

• Subtraction

• Addition

• Division

• Multiplication

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CCSS.HSA.REI.A.1

After removing the 1kg blocks, what is the new equation on the left-hand side?

• x

• 3x

• 3x - 2

• 3x + 2

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CCSS.7.EE.B.4A

What is the next step after simplifying the equation to 3x = 12?

• Divide both sides by 3.

• Multiply both sides by one-third.

• Subtract 2 from both sides.

• Add 2 to both sides.

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CCSS.6.EE.B.7

What is the value of X after solving the equation?

• 2 kg

• 3 kg

• 4 kg

• 5 kg

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CCSS.6.EE.B.7

How many 1kg blocks are left on the right-hand side after multiplying by one-third?

• 2

• 3

• 4

• 5

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CCSS.3.NF.A.2B

CCSS.3.NF.A.1

What does multiplying both sides by one-third represent physically?

• Adding more blocks to the scale.

• Doubling the number of blocks.

• Removing all blocks from the scale.

• Keeping a third of the original blocks.

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CCSS.HSA.REI.A.1

Why is it important to perform the same operation on both sides of the equation?

• To increase the total mass.

• To remove all variables.

• To keep the scale balanced.

• To make the equation more complex.

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CCSS.6.EE.B.7