Calculating pH and Percent Ionization of Weak Acids and Bases

Calculating pH and Percent Ionization of Weak Acids and Bases

Assessment

Interactive Video

Science

9th - 12th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

This video tutorial covers the calculation of pH for weak acid and base solutions, including the concepts of percent ionization and equilibrium constants (Ka and Kb). It explains the dissociation of strong acids and bases, the relationship between pH and pOH, and how to use ICE tables for equilibrium calculations. The video also discusses acid strength, the relationship between Ka and pKa, and provides practice problems to reinforce these concepts.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the pH value when the pOH is 10 at 25 degrees Celsius?

pH = 14

pH = 4

pH = 10

pH = 6

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which constant is used to describe the equilibrium of a weak acid in water?

Ka

Kc

Kb

Kw

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of Kw at 25 degrees Celsius?

1 x 10^-5

1 x 10^-14

1 x 10^-7

1 x 10^-10

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the pKa value represent in acid-base chemistry?

The product of pH and pOH

The negative logarithm of the acid dissociation constant

The base dissociation constant

The hydrogen ion concentration

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is percent ionization calculated for a weak acid?

Concentration of ionized acid divided by initial concentration times 100%

Concentration of H+ ions times initial concentration

Concentration of OH- ions divided by initial concentration

Initial concentration divided by concentration of ionized acid

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the pH of a 0.75 M acetic acid solution given Ka = 1.8 x 10^-5?

pH = 3.67

pH = 2.43

pH = 4.75

pH = 1.80

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find the pH of a solution from the hydroxide ion concentration?

pH = pOH + 7

pH = pOH - 14

pH = 14 - pOH

pH = 14 + pOH

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