Calculating Percent Composition and Empirical Formulas

Calculating Percent Composition and Empirical Formulas

Assessment

Interactive Video

Chemistry

9th - 12th Grade

Medium

Created by

Liam Anderson

Used 2+ times

FREE Resource

The video tutorial explains how to calculate the percent composition of elements in compounds, using examples like aluminum oxide and Fe2O3. It also covers the concepts of empirical and molecular formulas, demonstrating how to derive one from the other using molar mass. The tutorial concludes with a call to action for viewers to engage with the content.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the percent composition in a clothing tag represent?

Price of the clothing

Sizes available for the clothing

Fiber content in terms of percentage

Country of manufacture

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the percent composition of an element in a compound?

Element's mass * Total mass

Total mass / Element's mass

Total mass / Element's mass * 100

Element's mass / Total mass

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the percent composition of aluminum in 5.1 grams of aluminum oxide if it contains 2.7 grams of aluminum?

47.1%

52.9%

45%

50%

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you find the mass of oxygen in aluminum oxide if not given directly?

Subtract aluminum mass from total mass

Add aluminum mass to total mass

Multiply aluminum mass by two

Divide total mass by aluminum mass

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the percent composition of iron in Fe2O3?

30.05%

69.95%

50%

60%

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How would you calculate the grams of iron in 45 grams of Fe2O3?

Add 45 to 69.95 and divide by 100

Divide 45 by 69.95 and multiply by 100

Multiply 45 by 69.95 and divide by 100

Subtract 69.95 from 45 and multiply by 100

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the empirical formula of glucose?

C3H6O3

CH2O

C6H12O6

C2H4O2

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