
Finding Missing Sides with the Law of Sines

Interactive Video
•
Mathematics
•
6th - 10th Grade
•
Medium
+2
Standards-aligned

Ethan Morris
Used 2+ times
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the Law of Sines used for?
To find missing sides of a triangle when given two angles and one side
To find missing angles in a triangle
To calculate the area of a triangle
To prove triangles are congruent
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What information do we have about triangle ABC?
Three angles
One side and two angles
Two sides and one angle
Two angles and one side
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What ratio is compared in the Law of Sines?
The ratio of side lengths to their angles
The ratio of angles to their cosine values
The ratio of side lengths to their area
The ratio of sine of angles to their opposite sides
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you set up the equation using the Law of Sines?
By adding the sides to the sines of their opposite angles
By multiplying the sides by the sines of their opposite angles
By dividing the sides by the sines of their opposite angles
By equating the ratios of sides to the sines of their opposite angles
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the next step after setting up the equation with the Law of Sines?
Subtract the known angle from 180 degrees
Divide both sides by the known side
Add the known sides together
Cross multiply and solve for the unknown side
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of cross multiplying in the equation setup?
To isolate the unknown side
To find the value of the unknown angle
To eliminate the denominator
To simplify the equation
Tags
CCSS.HSG.SRT.C.8
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final step in solving for the unknown side using the Law of Sines?
Multiply both sides by the sine of the known angle
Subtract the sine of the known angle from both sides
Divide both sides by the sine of the known angle
Add the sine of the known angle to both sides
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
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