Partial Derivatives and Chain Rule

Partial Derivatives and Chain Rule

Assessment

Interactive Video

Mathematics

10th Grade - University

Hard

Created by

Emma Peterson

FREE Resource

This video tutorial introduces the chain rule for functions of multiple variables, focusing on the second case where variables depend on two parameters. It explains the concept of partial derivatives and demonstrates the calculation of these derivatives with respect to parameters t and s using a detailed example. The lesson concludes with a brief overview of the next topic, which involves generalizing the chain rule for functions of n variables depending on m parameters.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main topic of the second theorem discussed in the video?

Chain rule for functions of multiple variables

Limits of single-variable functions

Integration of multivariable functions

Optimization of functions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second case of the chain rule, what do the variables x and y depend on?

Three parameters

Two parameters, t and s

Only one parameter

No parameters

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the partial derivative of Z with respect to t in the given example?

2ts * e^x * sin(y) + s^2 * e^x * cos(y)

e^x * sin(y) + e^x * cos(y)

2ts * e^x * cos(y) + s^2 * e^x * sin(y)

e^x * sin(y) * cos(y)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function Z in the example provided?

Z = e^y * cos(x)

Z = e^y * sin(x)

Z = e^x * sin(y)

Z = e^x * cos(y)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the partial derivative of Z with respect to x in the example?

e^x * sin(y)

sin(y)

e^x * cos(y)

cos(y)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the partial derivative of Z with respect to y in the example?

cos(y)

e^x * sin(y)

e^x * cos(y)

sin(y)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of x in terms of s and t in the example?

x = s * t

x = s + t^2

x = s * t^2

x = s^2 * t

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