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Circle Equation Concepts

Circle Equation Concepts

Assessment

Interactive Video

Mathematics

7th - 10th Grade

Practice Problem

Hard

CCSS
HSG.GPE.A.1, 5.G.A.1, HSF.IF.A.2

Standards-aligned

Created by

Mia Campbell

FREE Resource

Standards-aligned

CCSS.HSG.GPE.A.1
,
CCSS.5.G.A.1
,
CCSS.HSF.IF.A.2
The video tutorial explains how to write the equation of a circle when the center is not at the origin. It begins by identifying the center of the circle as coordinates h and k. The instructor then demonstrates how to substitute these values into the circle equation. The process involves simplifying the equation by handling negative values, resulting in the final equation of the circle.

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5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why do we need to use a specific formula for the circle equation in this example?

Because the circle is not a perfect circle

Because the circle is not in the first quadrant

Because the center is not at the origin

Because the radius is unknown

Tags

CCSS.5.G.A.1

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the coordinates of the center of the circle in this example?

(3, -4)

(-3, 4)

(-4, 3)

(4, -3)

Tags

CCSS.HSG.GPE.A.1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step after identifying the center coordinates?

Calculate the radius

Substitute the coordinates into the circle equation

Draw the circle

Find the diameter

Tags

CCSS.HSF.IF.A.2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you handle the negative sign when substituting -3 into the equation?

Leave it as it is

Add it to the radius

Change it to a positive

Subtract it from the radius

Tags

CCSS.HSG.GPE.A.1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final equation of the circle?

(x + 3)^2 + (y - 4)^2 = 64

(x - 3)^2 + (y + 4)^2 = 64

(x - 3)^2 + (y - 4)^2 = 64

(x + 3)^2 + (y + 4)^2 = 64

Tags

CCSS.HSG.GPE.A.1

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