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  5. Identifying Equivalent Expressions Using The Distributive Property
Identifying Equivalent Expressions Using the Distributive Property

Identifying Equivalent Expressions Using the Distributive Property

Assessment

Interactive Video

Mathematics

6th - 10th Grade

Practice Problem

Medium

CCSS
6.EE.A.4, 6.EE.A.3, 6.EE.A.2B

+1

Standards-aligned

Created by

Jackson Turner

Used 10+ times

FREE Resource

Standards-aligned

CCSS.6.EE.A.4
,
CCSS.6.EE.A.3
,
CCSS.6.EE.A.2B
CCSS.7.EE.A.1
,

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical concept is being used to solve the problem?

Distributive property

Commutative property

Additive identity

Associative property

Tags

CCSS.6.EE.A.3

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of distributing 2 over the expression 5x + 3?

10x + 3

7x + 3

10x + 6

25x + 6

Tags

CCSS.6.EE.A.3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't the terms 10x and 6 be combined further?

They represent different mathematical operations.

One is a variable and the other is a constant.

One is an exponent and the other is a base.

They are like terms.

Tags

CCSS.6.EE.A.2B

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a correct application of the distributive property?

2(5x + 3) = 25x + 6

2(5x + 3) = 10x + 3

2(5x + 3) = 5x + 6

2(5x + 3) = 10x + 6

Tags

CCSS.6.EE.A.3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which answer choice is immediately identified as equivalent to the given expression?

Choice A

Choice B

Choice C

Choice D

Tags

CCSS.6.EE.A.4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is choice D not equivalent to the given expression?

It is a multiplication of the expression by itself.

It involves division instead of multiplication.

It is a completely different expression.

It represents subtraction instead of addition.

Tags

CCSS.6.EE.A.4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is choice E proven to be equivalent to the given expression?

By subtracting the constant from the variable

By multiplying each term by 2

By adding like terms together

By dividing each term by 2

Tags

CCSS.6.EE.A.4

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