This video tutorial teaches how to extend multiplication facts by using a simple trick for multiplying numbers that end in zero. The instructor explains the process with examples, showing how to handle larger numbers by focusing on non-zero digits and adding zeros accordingly. This method is useful for estimating products and is easy to perform mentally, making it a valuable tool for students.

What is the result of multiplying 8 by 6?

• 48

• 54

• 64

• 72

Tags

CCSS.3.OA.C.7

What happens when you multiply a number by 10 in terms of zeros?

• Adds one zero to the number

• Subtracts one zero

• Multiplies the number by 100

• No change

Tags

CCSS.3.OA.D.9

How do you multiply 80 by 6 using the trick mentioned?

• Multiply 8 by 6 and add one zero

• Multiply 8 by 6 and add two zeros

• Multiply 8 by 60 directly

• Divide 80 by 10 and then multiply by 6

Tags

CCSS.4.NBT.B.5

What is the first step in the trick for multiplying numbers that end in zero?

• Divide by 10

• Multiply the numbers directly

• Add all the zeros together

• Identify the non-zero digits

Tags

CCSS.4.NBT.B.5

How do you extend multiplication facts for large numbers?

• Multiply the non-zero digits and then add zeros according to the multiplication

• Multiply the numbers as they are

• Subtract zeros from both numbers before multiplying

• Add zeros before multiplying

Tags

CCSS.4.NBT.B.5

What is the result of 80 times 60?

• 4,800

• 480

• 8,000

• 800

Tags

CCSS.4.NBT.B.5

How many zeros are added when multiplying 8,000 by 4,000?

• Six zeros

• Four zeros

• Three zeros

• Five zeros

Tags

CCSS.5.NBT.B.5

What is the result of multiplying 40 by 800?

• 32,000

• 3,200

• 320

• 320,000

Tags

CCSS.5.NBT.B.5

What is the purpose of the multiplication trick taught in the video?

• To learn advanced calculus

• To reduce the number of multiplication steps

• To easily estimate products of large numbers

• To avoid using a calculator

Tags

CCSS.5.NBT.B.7

How does the trick help in mental math?

• By reducing the numbers to single digits

• By simplifying the multiplication process

• By eliminating the need for multiplication

• By using advanced algorithms

Tags

CCSS.3.OA.D.9