Exploring Area and Perimeter of Rectangles

The video tutorial explains how to determine the dimensions of a rectangular table given its perimeter and area. The table is longer than it is wide, and both dimensions are whole numbers. The tutorial walks through the process of setting up equations for the perimeter and area, and then uses trial and error to test different factor pairs of 24 to find the correct dimensions that satisfy both conditions. The solution is found to be a width of 4 feet and a length of 6 feet.

What are the given conditions for the rectangular table?

• Perimeter of 24 feet and area of 20 square feet

• Both length and width are even numbers

• Length is less than the width

• Perimeter of 20 feet and area of 24 square feet

What does the perimeter of a rectangle represent?

• The sum of all four sides

• Twice the sum of length and width

• The diagonal of the rectangle

• The product of length and width

How is the area of a rectangle calculated?

• Width divided by length

• Length plus width

• Length times width

• Length minus width

Why are whole numbers important for solving this problem?

• They make the table more stable

• They are required for the dimensions

• They simplify calculations

• They are easier to measure

What is the first pair of factors of 24 tried?

• 4 and 6

• 3 and 8

• 2 and 12

• 1 and 24

Why was the pair 1 and 24 not suitable?

• It did not satisfy the area condition

• It exceeded the perimeter condition

• It was not a pair of whole numbers

• It made the table too narrow

Which method was primarily used to solve for the table's dimensions?

• Algebraic manipulation

• Geometric proof

• Trial and error with factors

• Graphical representation

Which pair of dimensions satisfies both the area and perimeter conditions?

• 1 and 24

• 2 and 12

• 3 and 8

• 4 and 6

What is the width of the table?

• 2 feet

• 4 feet

• 6 feet

• 8 feet

What is the length of the table?

• 8 feet

• 4 feet

• 2 feet

• 6 feet