Understanding the Side Splitter Theorem

The video tutorial covers the sidesplitter challenge, focusing on solving for unknown variables x and y using proportions. It begins with an introduction to the problem, followed by detailed steps to find x and y using the sidesplitter theorem. The tutorial concludes with tips on effectively applying the theorem, emphasizing the importance of matching side lengths for accurate calculations.

What is the main concept introduced in the side splitter challenge?

• Using angles to find side lengths

• Solving equations with unknown variables

• Creating proportional segments with parallel sides

• Using base lengths for proportions

Which proportion is used to solve for x in the side splitter theorem?

• 2/x = 4/12

• x/2 = 12/4

• 4/x = 2/12

• x/4 = 2/12

Tags

CCSS.7.G.A.1

What is the value of x after solving the proportion?

• 8

• 6

• 4

• 10

Tags

CCSS.HSG.SRT.B.4

Which proportion is used to solve for y in the side splitter theorem?

• 2/6 = 4/y

• 4/2 = y/6

• 6/2 = y/4

• y/4 = 6/2

Tags

CCSS.5.MD.A.1

What is the value of y after solving the proportion?

• 10

• 12

• 16

• 14

Tags

CCSS.HSG.SRT.B.4

What is a key takeaway about using the side splitter theorem?

• It can be used with any triangle sides

• It requires knowing all side lengths

• It should not be used with base lengths

• It only works with right triangles

Tags

CCSS.HSG.SRT.B.4

What should you ensure when setting up proportions using the side splitter theorem?

• Use the longest side for the ratio

• Match up corresponding sides correctly

• Always use the base length

• Use angles instead of sides

Tags

CCSS.HSG.SRT.B.4

What happens if you use the base lengths in the side splitter theorem?

• The theorem still applies

• The proportions will be incorrect

• It simplifies the calculation

• It provides the same result