What is the main concept introduced in the side splitter challenge?

Understanding the Side Splitter Theorem

Interactive Video
•
Mathematics
•
7th - 10th Grade
•
Easy

Jackson Turner
Used 1+ times
FREE Resource
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8 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Using angles to find side lengths
Solving equations with unknown variables
Creating proportional segments with parallel sides
Using base lengths for proportions
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which proportion is used to solve for x in the side splitter theorem?
2/x = 4/12
x/2 = 12/4
4/x = 2/12
x/4 = 2/12
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the value of x after solving the proportion?
8
6
4
10
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which proportion is used to solve for y in the side splitter theorem?
2/6 = 4/y
4/2 = y/6
6/2 = y/4
y/4 = 6/2
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the value of y after solving the proportion?
10
12
16
14
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is a key takeaway about using the side splitter theorem?
It can be used with any triangle sides
It requires knowing all side lengths
It should not be used with base lengths
It only works with right triangles
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What should you ensure when setting up proportions using the side splitter theorem?
Use the longest side for the ratio
Match up corresponding sides correctly
Always use the base length
Use angles instead of sides
8.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens if you use the base lengths in the side splitter theorem?
The theorem still applies
The proportions will be incorrect
It simplifies the calculation
It provides the same result
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