Solving Systems of Equations

The video tutorial guides students through solving linear equations by isolating variables, substituting values, and using the distributive property. It demonstrates solving two exercises, highlighting the process of finding solutions and identifying infinite solutions. The tutorial emphasizes careful step-by-step problem-solving and provides guided practice for reinforcement.

What is the first step in solving a system of equations?

• Divide both equations by a constant

• Multiply both equations by a constant

• Add both equations together

• Solve one equation for one variable

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Which variable was chosen to solve for in the first equation?

• y

• z

• x

• w

Tags

CCSS.6.EE.A.3

What property is used to simplify the equation after substitution?

• Commutative Property

• Identity Property

• Distributive Property

• Associative Property

Tags

CCSS.8.EE.C.7A

What conclusion is reached when the equation simplifies to 0 = 0?

• No solution

• One solution

• Two solutions

• Infinite solutions

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

In exercise 11, which equation is solved first?

• 2x - 8y = 2

• x + 2y = -1

• x - 2y = -5

• x - 4y = 1

What is the value of x after solving the first equation in exercise 11?

• 3y - 4

• y + 2

• 4y + 1

• 2y - 5

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the next step after substituting the value of x in the second equation?

• Add the equations

• Multiply by a constant

• Combine like terms

• Divide by a constant

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the value of y after solving the combined equation?

• 1

• 2

• 0

• 3

Which original equation is used to find the value of x after finding y?

• x + 2y = -1

• x - 2y = -5

• 2x - 8y = 2

• x - 4y = 1

Tags

CCSS.8.EE.C.7B

What is the final value of x in exercise 11?

• -3

• 0

• 1

• 2

Tags

CCSS.8.EE.C.7B