Understanding Rational Expressions and Common Denominators

Understanding Rational Expressions and Common Denominators

Assessment

Interactive Video

Mathematics

6th - 8th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to add two rational expressions by finding a common denominator. It begins with identifying the least common multiple of the denominators and then adjusting the fractions to have this common denominator. The process involves multiplying the numerator and denominator by the same value to maintain the expression's value. The tutorial concludes with simplifying the resulting expression and stating the domain restrictions, emphasizing that x cannot be zero to avoid undefined expressions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the problem of adding two rational expressions?

Find a common denominator

Subtract the denominators

Multiply the numerators

Divide the expressions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to find the least common multiple when adding fractions?

To simplify the numerators

To make the fractions larger

To ensure the denominators are equal

To change the fractions to decimals

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the least common multiple of 6x to the fourth and 3x squared?

6x to the fourth

6x squared

3x to the fourth

3x squared

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you convert 3x squared to have a denominator of 6x to the fourth?

Multiply by 3x squared

Multiply by 2x

Multiply by 6x

Multiply by 2x squared

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What assumption is made about the variable x in the domain?

x can be any real number

x cannot be zero

x must be greater than zero

x must be a positive integer

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of adding the numerators 5 and 14x squared?

19

19x squared

5x squared + 14

14x squared + 5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't the expression 14x squared + 5 over 6x to the fourth be simplified further?

14 and 5 are both divisible by 2

5 has no x term

6x to the fourth is already simplified

The expression is already in decimal form

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