Understanding Parametric Equations

This video tutorial covers parametric equations, including their historical context, graphing techniques using a TI-89 calculator, algebraic confirmation of graphs, and the conversion between parametric and Cartesian equations. It also explains how to graph ellipses and find parametrization for line segments between points.

What is the primary purpose of using a third variable in parametric equations?

• To simplify complex equations

• To describe motion or curves not defined by a function

• To convert equations into Cartesian form

• To eliminate the need for graphing calculators

What is the significance of the parameter 't' in parametric equations?

• It is a constant

• It is a coefficient

• It is the independent variable

• It is the dependent variable

Which key sequence is used to graph parametric equations on a TI-89 calculator?

• Mode > Graph > 3 Polar

• Mode > Graph > 2 Parametric

• Mode > Graph > 1 Function

• Mode > Graph > 4 Sequence

Tags

CCSS.HSA.REI.A.2

What is the result of squaring both sides of the equation x = √y?

• x^2 = y

• x = y

• x = y^2

• x^2 = y^2

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CCSS.HSA.REI.A.2

What shape is represented by the parametric equations x = cos(t) and y = sin(t)?

• Hyperbola

• Ellipse

• Parabola

• Circle

Which of the following is a characteristic of an ellipse in parametric form?

• x = a sec(t), y = b csc(t)

• x = a cos(t), y = b sin(t)

• x = a sin(t), y = b cos(t)

• x = a tan(t), y = b cot(t)

How can you convert a parametric equation to a Cartesian equation using trigonometric identities?

• By integrating both equations

• By differentiating both equations

• By using the identity sin^2(t) + cos^2(t) = 1

• By solving for t in one equation and substituting

What is the first step in converting a Cartesian equation to a parametric equation?

• Solve for x in terms of y

• Solve for y in terms of x

• Replace x with t

• Replace y with t

Which method is used to eliminate the parameter in parametric equations?

• Algebraic substitution

• Graphical substitution

• Numerical integration

• Differential calculus

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CCSS.HSA.CED.A.3

What is the parametric equation for a line segment starting at (-2, 1) and ending at (3, 5)?

• x = 3 + 4t, y = 5 + 5t

• x = -2 + 5t, y = 1 + 4t

• x = 3 + 5t, y = 5 + 4t

• x = -2 + 4t, y = 1 + 5t

Tags

CCSS.HSA.CED.A.3