Understanding Systems of Equations

Understanding Systems of Equations

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to solve a system of three equations with three unknowns using the method of elimination. It discusses the possible outcomes: one solution, no solution, or infinite solutions. The tutorial demonstrates labeling equations, eliminating variables, and solving the system. It highlights the case of infinite solutions and how to express them using a parameter T. The video concludes with a graphical verification of the infinite solutions, showing the intersection of planes in space.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the possible outcomes when solving a system of three equations using the method of elimination?

Only infinite solutions

Only no solution

Only one solution

One solution, no solution, or infinite solutions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it beneficial to label equations when solving a system?

To confuse the solver

To keep the process organized

To avoid solving the system

To make the equations look more complex

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result when adding equations A and B in this system?

3x - 2z = 0

2x + 2z = 0

x - z = 0

3x + 2z = 0

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the equation 0 = 0 indicate about the system of equations?

The system has no solution

The system has one solution

The system has infinite solutions

The system is inconsistent

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can infinite solutions be expressed in terms of a new variable?

By using only fractions

By using only integers

By using a new variable like T

By using a constant value

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If z is expressed as T, what is the expression for x?

x = 5/3T

x = 3/2T

x = 2/3T

x = T

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you express y in terms of T using equation B?

y = 2/3T

y = T

y = 3/2T

y = 5/3T

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