Understanding Limits of Functions of Two Variables

Understanding Limits of Functions of Two Variables

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to evaluate limits of functions of two variables using direct substitution and algebraic techniques. It begins with an introduction to limits and the importance of continuity. The tutorial demonstrates direct substitution and graphical verification for a rational function. When direct substitution results in an indeterminate form, algebraic techniques like factoring are used to simplify the function and remove discontinuities. The tutorial concludes with a summary of the methods and graphical verification of the results.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in evaluating limits of functions of two variables?

Use algebraic techniques

Perform direct substitution

Check for indeterminate forms

Graph the function

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is direct substitution possible in the first limit problem?

The denominator is zero

The function is discontinuous

There are no domain restrictions

The numerator is zero

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of the first limit problem after direct substitution?

Infinity

0

1

Undefined

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What issue arises when performing direct substitution in the second limit problem?

The function is continuous

The result is an indeterminate form

The numerator is zero

The denominator is non-zero

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What algebraic technique is used to simplify the second limit problem?

Completing the square

Substitution

Factoring

Expanding

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What common factor is identified in the second limit problem?

x^2 + y^2

x^2 - y^2

x^4 - y^4

2x^2 + 2y^2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After simplification, what is the new expression for the second limit problem?

6 * (x^2 + y^2)

6 * (x^2 - y^2)

3 * (x^2 - y^2)

3 * (x^2 + y^2)

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