Vector-Valued Functions and Integration

Vector-Valued Functions and Integration

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to determine a vector-valued function R of T given its derivative and initial conditions. It covers the integration of each component separately, using integration as the inverse of differentiation. The tutorial demonstrates finding constants for each component by substituting initial conditions, resulting in the complete vector-valued function R of T.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the components of the derivative of the vector-valued function R(T)?

2t, sin T, e^2T

6t, 2 cos T, 3 e^T

2t + 6, sin T, 3 e^2T

2 + 6t, 2 sin T, 3 e^2T

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial condition given for the vector-valued function R(T)?

R(0) = (2, 5, 1)

R(0) = (1, 5, 2)

R(0) = (2, 1, 5)

R(0) = (5, 1, 2)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of integrating the derivative R'(T)?

To find the original vector-valued function R(T)

To find the derivative of R(T)

To solve for T

To determine the constant of integration

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integrated form of the X component of R(T)?

2T^2 + 3T + 5

3T^2 + 2T + 1

2T + 3T^2 + 5

2T + 6T^2 + 1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant C1 determined for the X component?

By using the initial condition R(0) = (5, 1, 2)

By solving the equation 2T + 3T^2 = 5

By differentiating the X component

By setting T = 1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integrated form of the Y component of R(T)?

-2 cos T + 3

2 sin T + 3

-2 sin T + 3

2 cos T + 3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant C2 determined for the Y component?

By using the initial condition R(0) = (5, 1, 2)

By differentiating the Y component

By setting T = 1

By solving the equation -2 cos T = 1

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