Understanding Quadratic Functions

Understanding Quadratic Functions

Assessment

Interactive Video

Mathematics

7th - 10th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to find the vertex of a quadratic function in standard form. It begins by introducing the standard form of a quadratic equation and identifying the coefficients. The tutorial then demonstrates how to calculate the x-coordinate of the vertex using the formula -b/2a and explains that this value is also the axis of symmetry. Next, it shows how to find the y-coordinate by substituting the x-coordinate back into the function. Finally, the video discusses graphing the quadratic function, noting that the parabola opens upwards because the coefficient of x^2 is positive.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to find the vertex of a quadratic function in standard form?

x = a / (2b), y = f(x)

x = b / (2a), y = f(x)

x = -b / (2a), y = f(x)

x = c / (2a), y = f(x)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the quadratic equation f(x) = x^2 - 8x + 5, what are the values of a, b, and c?

a = 1, b = 8, c = -5

a = 1, b = -8, c = -5

a = 1, b = 8, c = 5

a = 1, b = -8, c = 5

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the x-coordinate of the vertex for the function f(x) = x^2 - 8x + 5?

x = 8 / 2

x = -8 / 1

x = -8 / 2

x = 8 / 1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the x-coordinate of the vertex for the function f(x) = x^2 - 8x + 5?

x = 2

x = -2

x = 4

x = -4

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the y-coordinate of the vertex for the function f(x) = x^2 - 8x + 5?

y = 1

y = -1

y = 5

y = 0