Understanding Parabolas: Focus and Directrix

Understanding Parabolas: Focus and Directrix

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

CCSS
5.G.A.1

Standards-aligned

Created by

Mia Campbell

FREE Resource

Standards-aligned

CCSS.5.G.A.1
The video tutorial explains how to find the equation of a parabola given its focus and directrix. It starts by plotting the focus and directrix, then discusses the properties of parabolas, including the significance of the 'p' value. The tutorial guides viewers through calculating the vertex and deriving the equation, ensuring the parabola opens in the correct direction. Finally, it confirms the equation by plotting the vertex and checking its position relative to the focus and directrix.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the focus of the parabola in the given problem?

(-6, 2)

(6, -2)

(2, -6)

(-2, 6)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of the directrix in the problem?

y = -4

x = -4

y = 4

x = 4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In which direction does the parabola open?

Downwards

Right

Upwards

Left

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general form of the parabola's equation?

(y - H)^2 = 4P(x - K)

(x - H)^2 = 4P(y - K)

(y - K)^2 = 4P(x - H)

(x - K)^2 = 4P(y - H)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the distance between the focus and directrix related to 'p'?

2|p|

|p|

4|p|

|p|/2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of 'p' for the parabola?

10

-5

-10

5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the vertex of the parabola determined?

By moving 5 units to the right of the focus

By moving 5 units to the left of the focus

By moving 5 units above the focus

By moving 5 units below the focus

Tags

CCSS.5.G.A.1

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