Understanding Rectangles and Quadratic Equations

Understanding Rectangles and Quadratic Equations

Assessment

Interactive Video

Mathematics

7th - 10th Grade

Hard

Created by

Lucas Foster

FREE Resource

The video tutorial explains how to determine the original dimensions of a rectangle given that its length is 8 feet longer than its width. When each side is increased by 8 feet, the area becomes four times larger. The process involves setting up an equation based on these conditions, solving a quadratic equation, and using trial and error to factor it. The final solution reveals the original width and length of the rectangle.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between the length and width of the original rectangle?

The length and width are equal.

The length is 8 feet longer than the width.

The length is twice the width.

The width is 8 feet longer than the length.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the area of the rectangle when each side is increased by 8 feet?

The area is doubled.

The area is tripled.

The area is multiplied by four.

The area remains the same.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the area of the original rectangle expressed in terms of x?

x * (x + 16)

x^2 + 8x

x * (x + 8)

x^2 + 16x

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation set up to find the original dimensions of the rectangle?

x * (x + 16) = 4 * (x + 8)

4 * (x + 8) = x * (x + 16)

x * (x + 8) = 4 * (x + 8) * (x + 16)

4x * (x + 8) = (x + 8) * (x + 16)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the quadratic equation?

Add x^2 to both sides.

Subtract x^2 from both sides.

Multiply both sides by 4.

Divide both sides by x.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What method is used to solve the quadratic equation in this problem?

Trial and error

Using the quadratic formula

Completing the square

Graphing

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the factors used in the trial and error method?

8 and 16

-8 and -16

-16 and 8

-8 and 16

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