
Understanding Eigenvalue Problems in Fourier Series

Interactive Video
•
Mathematics, Physics
•
11th Grade - University
•
Hard

Amelia Wright
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is an eigenvalue in the context of this lesson?
A variable that changes with time
A constant that multiplies a function
A number that allows a non-zero solution to a differential equation
A number that solves a polynomial equation
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When Lambda is greater than zero, what form does the general solution take?
x = a e^t + b e^-t
x = a t + b
x = a cos(sqrt(Lambda) t) + b sin(sqrt(Lambda) t)
x = a sinh(t) + b cosh(t)
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
For Lambda greater than zero, what are the positive eigenvalues?
Lambda = k^3 for k > 0
Lambda = 2k for k >= 0
Lambda = k^2 for k >= 1
Lambda = k for any integer k
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the corresponding eigenfunction for Lambda equals zero?
x = t
x = 1
x = sin(t)
x = cos(t)
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When Lambda equals zero, what can be said about the value of 'a' in the general solution?
'a' must be zero
'a' can be any real number
'a' must be one
'a' is undefined
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the general solution form when Lambda is less than zero?
x = a t + b
x = a cos(t) + b sin(t)
x = a cosh(sqrt(-Lambda) t) + b sinh(sqrt(-Lambda) t)
x = a e^t + b e^-t
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why are there no negative eigenvalues when Lambda is less than zero?
Because the hyperbolic sine function is never zero
Because the characteristic equation has no real roots
Because the solution is always zero
Because the input to the hyperbolic sine function is always zero
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