Differential Equations Concepts Review

Differential Equations Concepts Review

Assessment

Interactive Video

Mathematics

10th Grade - University

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to solve a second order linear homogeneous differential equation by finding two solutions over an open interval from zero to infinity. It begins by noting the absence of a y term, allowing for a simpler solution. A substitution is made to convert the equation to a first order differential equation, which is then solved using separation of variables and integration. The general solution is derived, and the video concludes by discussing the linear independence of the solutions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of differential equation is being solved in the video?

Partial differential

Second order linear homogeneous

First order linear

Non-linear

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is one solution to the differential equation a constant?

Because the equation is first order

Because there is no y term in the equation

Because the equation is partial

Because the equation is non-linear

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is made to convert the second order equation to a first order equation?

Letting W equal y

Letting W equal y Prime

Letting W equal y double Prime

Letting W equal x

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What method is used to solve the first order differential equation?

Fourier series

Integration by parts

Separation of variables

Laplace transform

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integral of 1 divided by w dw?

Natural log w

1/w

w

e^w

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general solution to the differential equation?

y = C sub 4 x squared + C sub 2

y = C sub 4 x cubed + C sub 3

y = C sub 4 x squared + C sub 3

y = C sub 4 x + C sub 3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the two linearly independent solutions identified?

y1 = x squared, y2 = x cubed

y1 = C, y2 = x squared

y1 = C, y2 = x

y1 = x, y2 = x squared

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