Differential Equations and Solutions

Differential Equations and Solutions

Assessment

Interactive Video

Mathematics

11th Grade - University

Practice Problem

Hard

CCSS
HSA.CED.A.4, 8.EE.C.8B, HSA-REI.B.4B

+2

Standards-aligned

Created by

Lucas Foster

FREE Resource

Standards-aligned

CCSS.HSA.CED.A.4
,
CCSS.8.EE.C.8B
,
CCSS.HSA-REI.B.4B
CCSS.6.EE.B.7
,
CCSS.HSA.REI.C.6
,
The video tutorial explains how to solve an initial value problem using the method of substitution. It covers identifying substitutions for Bernoulli and homogeneous equations, solving the differential equation by making it separable, and integrating both sides. The tutorial also discusses the use of constants and graphing the solution to verify it fits the initial condition. The final solution is presented, and the graph is shown to pass through the given point, confirming the solution's accuracy.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary method used to solve the initial value problem in this tutorial?

Laplace transforms

Partial fraction decomposition

Method of substitution

Integration by parts

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which type of differential equation is identified after dividing by X?

Bernoulli equation

Linear equation

Homogeneous equation

Exact equation

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is made to transform the differential equation into a separable form?

Z = x^2

W = x/y

U = y/x

V = y/x

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What technique is used to integrate the left side of the equation?

Integration by parts

Trigonometric substitution

Partial fraction decomposition

U substitution

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of exponentiating both sides of the equation?

A linear equation

A quadratic equation

An exponential equation

A logarithmic equation

Tags

CCSS.HSA.CED.A.4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final form of V after solving the equation?

V = c x^2 - 1/2

V = c x^-2 + 1/2

V = c x^2 + 1/2

V = c x^-2 - 1/2

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the particular solution for y after back substitution?

y = 3/2x - x/2

y = 3x/2 - x^2/2

y = 3/x - x/2

y = 3x - x^2/2

Tags

CCSS.HSA-REI.B.4B

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