Differential Equations and Initial Value Problems

The video tutorial explains how to solve an initial value problem involving a differential equation. It begins by introducing the problem and its initial conditions, then discusses why separation of variables cannot be directly applied. The tutorial demonstrates factorization to enable separation of variables, followed by integration to solve for the constant using initial conditions. The general solution is derived, and the equation is solved for x using exponential form. The tutorial concludes with a summary of the solution process.

What is the initial value problem presented in the video?

• X Prime equals 5x t squared minus 5t squared with X of zero equals four

• X Prime equals 4x t squared minus 4t squared with X of zero equals three

• X Prime equals 2x t squared minus 2t squared with X of zero equals one

• X Prime equals 3x t squared minus 3t squared with X of zero equals two

Why can't the method of separation of variables be used initially?

• The equation is already solved

• There is no product of a function of X and a function of t

• The equation is not linear

• The initial condition is not given

Tags

CCSS.HSA-REI.B.4B

What is the first step in rewriting the differential equation?

• Add a constant to both sides

• Multiply both sides by t

• Replace X Prime with DX DT

• Divide both sides by x

Tags

CCSS.HSA-REI.B.4B

What is factored out from the right side of the equation?

• t squared

• 3x

• x minus 1

• 3t squared

What form does the equation take after multiplying by DT?

• 1 divided by x minus 1 DX equals 3t squared DT

• DX equals 3t squared DT

• x minus 1 equals 3t squared

• x equals t cubed

What is the integral of 3t squared with respect to t?

• 3t cubed

• 3t squared

• t cubed

• t squared

How is the constant C determined?

• By setting t to zero and solving for x

• By factoring the equation

• By substituting the initial condition into the integrated equation

• By differentiating the equation

What is the general solution for x?

• x equals e to the power of t cubed plus one

• x equals t cubed plus one

• x equals t squared plus one

• x equals e to the power of t squared plus one

Tags

CCSS.HSF.BF.B.5

What is the equivalent exponential equation for the natural log equation?

• e raised to the power of t cubed equals the absolute value of x minus one

• e raised to the power of t squared equals the absolute value of x minus one

• e raised to the power of t squared equals x minus one

• e raised to the power of t cubed equals x minus one

Tags

CCSS.7.EE.B.4A

What is the final step to solve for x?

• Divide both sides by e

• Add one to both sides

• Subtract one from both sides

• Multiply both sides by e

Tags

CCSS.7.EE.B.4A