Differential Equations and Integrals

Differential Equations and Integrals

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Practice Problem

Hard

CCSS
8.EE.C.8B

Standards-aligned

Created by

Lucas Foster

FREE Resource

Standards-aligned

CCSS.8.EE.C.8B
The video tutorial explains how to find the general solution to the differential equation Y' = -XY²/3, including singular solutions. It begins by identifying y = 0 as a singular solution and then uses the separation of variables technique to solve the equation. The process involves rearranging terms, integrating both sides, and solving for y. The final general solution is y = 6/(x² + D), where D is a constant. The tutorial also emphasizes the importance of recognizing singular solutions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial differential equation given in the problem?

Y' = -X^2Y/3

Y' = XY^2/3

Y' = X^2Y/3

Y' = -XY^2/3

Tags

CCSS.8.EE.C.8B

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a singular solution in the context of this problem?

A solution that is zero

A solution that is always negative

A solution that is constant

A solution that is always positive

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What technique is used to solve the differential equation when Y is not zero?

Partial fraction decomposition

Laplace transform

Separation of variables

Integration by parts

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of multiplying both sides of the equation by negative three divided by Y squared?

To remove the denominator and negative sign

To eliminate the variable X

To integrate directly

To simplify the equation

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integral of X with respect to X?

X^2/2

X^2

X^3/3

2X

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After integration, what form does the left side of the equation take?

3Y

3/Y

Y/3

Y^3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is performed to solve for Y after integration?

Taking the square root

Taking the reciprocal

Multiplying by a constant

Differentiating again

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