Differential Equations and Initial Conditions

Differential Equations and Initial Conditions

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to solve a differential equation using the inverse function theorem and integration. It starts with rewriting the equation in Leibniz notation, applies the inverse function theorem, and integrates to find the general solution. The initial condition is used to determine the particular solution, and the equation is solved for y. Finally, the solution is verified graphically to ensure correctness.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial condition given for the differential equation Y' = y^3?

y(0) = 0

y(0) = 1

y(1) = 1

y(1) = 0

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which theorem is used to rewrite the differential equation in terms of DX/Dy?

Pythagorean Theorem

Mean Value Theorem

Inverse Function Theorem

Fundamental Theorem of Calculus

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general solution form obtained after integrating the differential equation?

X(y) = y^3 + C

X(y) = 1/(2y^2) + C

X(y) = -1/(2y^2) + C

X(y) = y^2 + C

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant C determined in the particular solution?

By setting y = 0

By setting x = 1

By using the initial condition y(0) = 1

By differentiating the general solution

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the constant C in the particular solution?

1

0

1/2

-1/2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is performed to isolate the term with y^2 in the equation?

Division

Multiplication

Subtraction

Addition

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final form of y after solving the equation?

y = ±√(2/(1-x))

y = ±√(1/(2x-1))

y = ±√(1/(x-2))

y = ±√(1/(1-2x))

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