Coffee Temperature and Cooling Concepts

Coffee Temperature and Cooling Concepts

Assessment

Interactive Video

Mathematics, Physics, Science

10th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains an application of Newton's Law of Cooling, focusing on solving an initial value problem using separation of variables. It begins with a scenario where Bob wants to drink his coffee at 60°C. The tutorial covers setting up the differential equation, solving it, and determining the constants using initial conditions. Finally, it calculates the time required for the coffee to cool to the desired temperature and provides a graphical representation of the solution.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial temperature of Bob's coffee?

22 degrees Celsius

60 degrees Celsius

85 degrees Celsius

89 degrees Celsius

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the ambient temperature in the room?

60 degrees Celsius

22 degrees Celsius

85 degrees Celsius

89 degrees Celsius

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to Newton's Law of Cooling, the rate of temperature change is proportional to what?

The ambient temperature

The time elapsed

The initial temperature

The difference between ambient and coffee temperature

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What technique is used to solve the differential equation in this problem?

Laplace transform

Partial fraction decomposition

Integration by parts

Separation of variables

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the constant 'D' determined from the initial condition?

67

22

89

85

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant 'K' determined in the solution process?

By using the desired drinking temperature

By using the ambient temperature

By using the second temperature measurement

By using the initial temperature

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final equation used to determine when Bob can drink his coffee?

T = 22 + 67e^(-0.0616t)

T = 22 + 67e^(0.0616t)

T = 60 + 67e^(-0.0616t)

T = 60 + 22e^(-0.0616t)

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