Understanding Initial Value Problems and Picard's Theorem

Understanding Initial Value Problems and Picard's Theorem

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explores initial value problems in differential equations, focusing on determining the existence and uniqueness of solutions using Picard's theorem. Two examples are discussed: the first demonstrates a unique solution for y' = xy, while the second shows the non-existence of a solution for y' = x/(x^2-1) due to discontinuity at a critical point.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does Picard's theorem require for a solution to exist?

The function must be linear.

The initial condition must be zero.

f(x, y) must be continuous near the initial point.

f(x, y) must be differentiable.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first example, what is the function f(x, y)?

x + y

x / y

x - y

x * y

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the solution to the first example unique?

Because the partial derivative with respect to y is zero.

Because the partial derivative with respect to y is continuous.

Because the function is not defined at the initial point.

Because the function is linear.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What method is used to solve the first example?

Laplace transform

Separation of variables

Integration by parts

Fourier series

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general solution form for the first example?

y = c * e^(x^2)

y = c * e^(1/2 * x^2)

y = c * x

y = c * x^2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second example, why is f(x, y) not defined at the initial point?

Because the numerator becomes zero.

Because x is zero.

Because y is zero.

Because the denominator becomes zero.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main reason for the absence of a solution in the second example?

The function is not continuous.

The function is not differentiable.

The function is not defined at the initial point.

The function is not linear.

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?