Definite Integral Evaluation using U-Substitution

Definite Integral Evaluation using U-Substitution

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Liam Anderson

FREE Resource

This lesson demonstrates how to evaluate a definite integral using u-substitution. It begins by identifying the need for u-substitution due to the integrand's structure. The process involves defining u, solving for dx, and adjusting the limits of integration. The video shows two methods: evaluating the integral in terms of u and in terms of x, both yielding the same result. Finally, it provides a graphical interpretation of the integral, illustrating the area under the curve.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is u-substitution necessary for evaluating the given integral?

Because the integrand is a constant function.

Because the integrand is the sine of one-half x.

Because the integrand is the sine of x.

Because the integrand is a simple polynomial.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the differential du in terms of dx for the substitution u = 1/2 x?

du = 1/2 dx

du = 2 dx

du = dx

du = 3 dx

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you adjust the limits of integration when using u-substitution?

By keeping the original limits of x.

By substituting the x-values into u = 1/2 x.

By multiplying the limits by 2.

By adding 1 to each limit.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the antiderivative of sine u?

cosine u

-cosine u

sine u

-sine u

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of the definite integral after evaluating using u-substitution?

8

2

0

4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the antiderivative expressed when evaluating directly in terms of x?

2 cosine (1/2 x)

-2 cosine (1/2 x)

-2 cosine x

2 sine (1/2 x)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of the integral when evaluated directly in terms of x?

0

4

8

2

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