Vector Magnitude and Direction Concepts

Vector Magnitude and Direction Concepts

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Emma Peterson

FREE Resource

The video tutorial explains how to find the magnitude and direction of a vector given in component form. It begins by sketching the vector in standard position, then uses the Pythagorean theorem to calculate the magnitude. The direction is determined using the arctangent function, ensuring the angle is within the correct interval. The tutorial emphasizes the importance of graphing the vector and checking the angle's quadrant.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial point of a vector in standard position?

At the origin

At the terminal point

At the midpoint

At the endpoint

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the terminal point of a vector with components 3 and -6?

(3, -6)

(-3, 6)

(6, -3)

(-6, 3)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine the magnitude of a vector using its components?

By adding the components

By subtracting the components

By using the Pythagorean theorem

By multiplying the components

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for calculating the angle theta using arctangent?

Theta equals arctangent of x divided by y

Theta equals arctangent of y divided by x

Theta equals arctangent of x plus y

Theta equals arctangent of y minus x

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the range of the arctangent function?

0 to 180 degrees

-180 to 180 degrees

0 to 360 degrees

-90 to 90 degrees

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the simplified magnitude of a vector with components 3 and -6?

3 square root 5

5 square root 3

9 square root 5

6 square root 3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you adjust a negative angle to find the direction angle in the correct range?

Subtract 90 degrees

Subtract 180 degrees

Add 360 degrees

Add 90 degrees

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