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Partial Fraction Decomposition Concepts

Partial Fraction Decomposition Concepts

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Practice Problem

Hard

CCSS
HSA.APR.D.6

Standards-aligned

Created by

Aiden Montgomery

FREE Resource

Standards-aligned

CCSS.HSA.APR.D.6
This video tutorial introduces partial fraction decomposition, a method used to simplify rational functions for easier integration in calculus. It explains the process of breaking down complex rational expressions into simpler ones, detailing the steps involved, including factoring the denominator and solving for coefficients. The tutorial provides two examples, demonstrating the decomposition of rational expressions with distinct and repeated factors, highlighting the practical application of this technique in calculus.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary purpose of partial fraction decomposition in calculus?

To simplify complex rational expressions for easier integration

To solve differential equations

To multiply rational expressions

To find the derivative of rational functions

Tags

CCSS.HSA.APR.D.6

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What must be done if the degree of the numerator is greater than the degree of the denominator before performing partial fraction decomposition?

Subtract the denominator from the numerator

Multiply the numerator by the denominator

Divide the denominator into the numerator

Add a constant to the numerator

Tags

CCSS.HSA.APR.D.6

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How should each distinct linear factor in the form ax + b be represented in partial fraction decomposition?

As a term with a single variable in the numerator

As a constant

As a term with a repeated variable in the numerator

As a quadratic term

Tags

CCSS.HSA.APR.D.6

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In partial fraction decomposition, how are repeated quadratic factors handled?

By converting them into linear factors

By ignoring the repeated factors

By including multiple terms for each power of the factor

By including a single term for each factor

Tags

CCSS.HSA.APR.D.6

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving for constants in a partial fraction decomposition example?

Multiply by the least common denominator

Select convenient values for x

Factor the numerator

Integrate the expression

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first example, what value of x is used to solve for constant b?

x = 0

x = -3

x = 1

x = -5

Tags

CCSS.HSA.APR.D.6

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of the partial fraction decomposition for the expression 2/(x+3)(x+5)?

2/(x+3) + 2/(x+5)

2/(x+3) - 2/(x+5)

1/(x+3) - 1/(x+5)

1/(x+3) + 1/(x+5)

Tags

CCSS.HSA.APR.D.6

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