Solving Quadratic Equations and Solutions

Solving Quadratic Equations and Solutions

Assessment

Interactive Video

Mathematics

7th - 10th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to solve a quadratic equation by using substitution. It begins by identifying the equation's quadratic form and introduces a substitution method to simplify it. The tutorial then demonstrates factoring the simplified equation and solving for the variable y. Finally, it verifies the solutions by substituting them back into the original equation to ensure they are correct.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial step in identifying the quadratic form of the given equation?

Identifying the factors of y minus five

Clearing the parentheses

Factoring the equation

Performing a substitution

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is made to simplify the equation?

Let u equal y

Let u equal y plus five

Let u equal y squared

Let u equal y minus five

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After substitution, what form does the equation take?

u squared minus six equals negative u

u squared plus six equals u

u squared minus six equals u

u squared plus six equals negative u

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the factors of the simplified equation u squared plus u minus six?

(u + 2)(u - 3)

(u - 2)(u + 3)

(u + 1)(u - 6)

(u - 1)(u + 6)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the equation rewritten in terms of y after factoring?

(y - 3)(y + 5)

(y - 7)(y - 2)

(y - 5)(y - 3)

(y - 2)(y + 7)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the solutions for y after solving the equation?

y equals 5 or y equals 3

y equals 4 or y equals 0

y equals 7 or y equals 2

y equals 6 or y equals 1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of verifying the solutions?

To simplify the equation further

To find additional solutions

To confirm the solutions satisfy the original equation

To ensure the solutions are unique

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