Compensation Method in Subtraction

Compensation Method in Subtraction

Assessment

Interactive Video

Mathematics

5th - 8th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial introduces an alternative method for subtracting mixed numbers, focusing on the compensation method. It begins by reviewing common methods, such as finding a common denominator and converting to improper fractions. The compensation method simplifies subtraction by converting the subtrahend to a whole number, making the process easier. Two examples demonstrate this method, highlighting its efficiency when an exchange is required. The tutorial emphasizes that the compensation method is only necessary when direct subtraction is not possible.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in subtracting mixed numbers using common methods?

Add the fractions directly

Find the least common denominator

Subtract the whole numbers first

Convert to improper fractions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the common method, what do you do if you cannot subtract the fractions directly?

Use a calculator

Add a whole number to the minuend

Convert to decimals

Perform an exchange with the whole number

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main advantage of the compensation method?

It simplifies subtraction by converting to whole numbers

It uses decimals instead of fractions

It avoids finding a common denominator

It requires fewer calculations

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the compensation method, what is added to the subtrahend to make it a whole number?

An improper fraction

A decimal

A proper fraction

A whole number

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When using the compensation method, what must be done to maintain an equivalent difference?

Subtract the same fraction from the minuend

Add the same fraction to the minuend

Divide the minuend by the same fraction

Multiply the minuend by the same fraction

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example of 6 and 1/3 minus 3 and 3/4, what is the least common denominator used?

10

8

15

12

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of 6 and 1/3 minus 3 and 3/4 using the compensation method?

2 and 1/12

2 and 7/12

3 and 1/12

3 and 7/12

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