Understanding Absolute Extrema in Multivariable Calculus

Understanding Absolute Extrema in Multivariable Calculus

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to find the absolute extrema of a function f(x, y) within a bounded region defined by a circle with a radius of four. It covers the process of finding critical points by setting first-order partial derivatives to zero or undefined, and explains why there are no critical points in this scenario. The tutorial then shifts focus to finding extrema on the boundary using substitution to convert the function into one variable. It demonstrates the use of calculus techniques to derive and solve for extrema, ultimately identifying the absolute maximum and minimum values.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the shape of the bounded region where we are finding the absolute extrema?

A square centered at the origin

A circle centered at the origin

A triangle centered at the origin

A rectangle centered at the origin

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in finding the absolute extrema on a bounded region?

Use Lagrange multipliers

Determine the function values at endpoints

Find the second-order partial derivatives

Find the critical points in the bounded region

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why are there no critical points in the bounded region for this function?

The function is not continuous

The function is not differentiable

The partial derivatives are never zero or undefined

The function is a constant

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is used to convert the function into one variable?

x = y^2 - 16

y = x^2 + 16

y = ±√(16 - x^2)

x = ±√(16 - y^2)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function G(x) derived from the substitution?

G(x) = 4x - 5√(16 - x^2)

G(x) = 4x + 5√(16 - x^2)

G(x) = 5x - 4√(16 - x^2)

G(x) = 5x + 4√(16 - x^2)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What technique is used to find the derivative of G(x)?

Chain rule

Implicit differentiation

Quotient rule

Product rule

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the critical points of G(x) on the interval [-4, 4]?

x = 0

x = ±4

x = ±16/√41

x = ±20/41

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