Vector-Valued Functions and Integration

Vector-Valued Functions and Integration

Assessment

Interactive Video

Mathematics

11th Grade - University

Practice Problem

Hard

CCSS
HSN.VM.A.2

Standards-aligned

Created by

Emma Peterson

FREE Resource

Standards-aligned

CCSS.HSN.VM.A.2
This video tutorial covers the integration of vector-valued functions, focusing on finding specific anti-derivatives given initial conditions. Two examples are provided: the first involves basic polynomial functions, while the second incorporates trigonometric functions and requires substitution. The tutorial concludes with a brief introduction to definite integration of vector-valued functions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal when integrating vector-valued functions in this lesson?

To find the derivative of a function

To determine the specific anti-derivative given an initial condition

To calculate definite integrals

To solve differential equations

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first example, what is the initial condition given for R(0)?

R(0) = 0

R(0) = 2I + 1J

R(0) = 3I + 4J

R(0) = 1I + 2J

Tags

CCSS.HSN.VM.A.2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find the constant C1 in the first example?

By setting the X component to zero

By setting the X component to one

By setting the Y component to zero

By setting the Z component to two

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is used to integrate sin(2T) in the second example?

U = 2T

U = T

U = cos(T)

U = sin(T)

Tags

CCSS.HSN.VM.A.2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integral of 1/(1 + T^2) in the second example?

sin(T)

ln(T)

cos(T)

arctan(T)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second example, what is the initial condition given for R(0)?

R(0) = 2I + 3J + K

R(0) = 3I - 2J + K

R(0) = I + J + K

R(0) = 0

Tags

CCSS.HSN.VM.A.2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant C2 determined in the second example?

By setting the Y component to two

By setting the Z component to one

By setting the Y component to -2

By setting the X component to zero

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