Garden Dimensions and Area Problems

Garden Dimensions and Area Problems

Assessment

Interactive Video

Mathematics

6th - 8th Grade

Hard

Created by

Liam Anderson

FREE Resource

The video tutorial explains how to solve a problem involving a rectangular garden where the length is four feet longer than the width, and the perimeter is 192 feet. The teacher guides through setting up an equation to find the width, solving it, and then calculating the area of the garden using the derived dimensions. The process involves understanding the relationship between length and width, formulating and solving a linear equation, and applying the formula for the area of a rectangle.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between the length and width of the garden?

The length is twice the width.

The length is four feet longer than the width.

The length is equal to the width.

The length is four feet shorter than the width.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the width of the garden is represented as x, how can the length be expressed?

x - 4

x + 4

4x

2x

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation represents the perimeter of the garden?

x + 4x = 192

4x + 4 = 192

2x + 2(x + 4) = 192

x + (x + 4) = 192

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the equation for x?

Divide both sides by 2.

Add 8 to both sides.

Subtract 8 from both sides.

Multiply both sides by 4.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of x, representing the width of the garden?

44 feet

48 feet

46 feet

50 feet

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the length of the garden once x is found?

48 feet

44 feet

46 feet

50 feet

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What formula is used to calculate the area of the garden?

Length + Width

Length - Width

Length x Width

2 x (Length + Width)

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