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Factoring Quadratic Equations Methods

Factoring Quadratic Equations Methods

Assessment

Interactive Video

Mathematics

8th - 10th Grade

Practice Problem

Hard

CCSS
HSA-REI.B.4B, HSA.APR.D.6

Standards-aligned

Created by

Amelia Wright

FREE Resource

Standards-aligned

CCSS.HSA-REI.B.4B
,
CCSS.HSA.APR.D.6
This video tutorial covers how to factor and solve quadratic equations where the leading coefficient is not 1 and not a common factor. It reviews three methods: trial and error, grouping, and bottoms up, focusing on the trial and error method. Two examples are provided to demonstrate the process of factoring and solving quadratic equations using this method, highlighting the importance of selecting the correct factors to achieve the desired middle term.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the video tutorial?

Solving linear equations

Factoring and solving quadratic equations

Graphing quadratic functions

Solving cubic equations

Tags

CCSS.HSA.APR.D.6

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which method is being reviewed in detail in this video?

Bottoms up method

Synthetic division

Grouping method

Trial and error method

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first example, what are the possible first terms for the binomial factors?

6X and X

5X and X

4X and X or 2X and 2X

3X and X

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the correct factorization of the trinomial in the first example?

(2X - 3)(2X + 7)

(4X + 3)(X - 7)

(4X - 3)(X + 7)

(2X + 3)(2X - 7)

Tags

CCSS.HSA-REI.B.4B

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the solutions to the quadratic equation in the first example?

X = 3/4 and X = -7

X = 1/2 and X = -5

X = 1/4 and X = -8

X = 2/3 and X = -6

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second example, what must the first terms of the binomial factors be?

4X and X

3X and X

5X and X

2X and X

Tags

CCSS.HSA-REI.B.4B

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't a multiple of 3 be used in the second position of the binomial with 3X?

It would make the equation unsolvable

It would create a common factor

It would not affect the equation

It would result in a negative product

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