Integration by Substitution Concepts

Integration by Substitution Concepts

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Mia Campbell

FREE Resource

This video tutorial introduces the technique of integration by substitution, a method used to evaluate integrals that do not fit basic formulas. The instructor explains how to choose a substitution, rewrite the integral in terms of a new variable, and solve it. A detailed example is provided, demonstrating the process step-by-step. The video concludes with a note on potential variations in the method and mentions upcoming examples in future videos.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is integration by substitution used?

To simplify integrals that fit basic formulas

To evaluate integrals that do not fit basic formulas

To differentiate complex functions

To solve algebraic equations

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in the substitution process?

Compute the differential

Integrate in terms of the new variable

Rewrite the integral

Choose a substitution

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of computing the differential in substitution?

To differentiate the function

To find the anti-derivative

To check the answer

To match it with part of the original integral

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After rewriting the integral in terms of the new variable, what is the next step?

Choose a new substitution

Integrate in terms of the new variable

Check the answer by differentiating

Compute the differential

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example problem, what was chosen as the substitution 'u'?

X to the 7th

4X cubed

X to the 4th - 1

X to the 4th

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final step after integrating in terms of 'u'?

Rewrite the result in terms of x

Check the answer by differentiating

Choose a new substitution

Compute the differential

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What was the anti-derivative obtained in the example problem?

X to the 4th - 1

U to the 8th divided by 8 + C

4X cubed DX

1/8 x (X to the 4th - 1) raised to the 8th + C

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